1/2(2x^2+8)=20

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Solution for 1/2(2x^2+8)=20 equation: 



1/2(2x^2+8)=20

We move all terms to the left:

1/2(2x^2+8)-(20)=0



Domain of the equation: 2(2x^2+8)!=0

x∈R



We multiply all the terms by the denominator


-20*2(2x^2+8)+1=0

Wy multiply elements

-40x(2+1=0

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